Asked by Anonymous
What mass of ammonia is necessary to produce 500 kJ of heat?
4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) ΔrH = -906 kJ mol-1
4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) ΔrH = -906 kJ mol-1
Answers
Answered by
DrBob222
If this is REALLY 906 kJ/MOLE that is 906 kJ/17 g NH3.
Then 17 x (500/906) = ? g NH3 required.
Then 17 x (500/906) = ? g NH3 required.
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