Question
3. Two vehicles collide at a 90 degree intersection. If the momentum of vehicle A is
6.10 x10^5 kg km/h south and the momentum of vehicle B is 7.20 x 10^5 kg km/h
east, what is the magnitude of the resulting momentum of the final mass?
6.10 x10^5 kg km/h south and the momentum of vehicle B is 7.20 x 10^5 kg km/h
east, what is the magnitude of the resulting momentum of the final mass?
Answers
Henry
M1*V1 + M2*V2 = -6.10*10^5i + 7.20*10^5.
Tan A = Y/X = (-6.10*10^5)/7.20*10^5 = -0.84722, A = -40.3o = 40.3o S. of E.
Resulting momentum =
X/Cos A = 7.20^10^5/Cos(-40.3) =
Tan A = Y/X = (-6.10*10^5)/7.20*10^5 = -0.84722, A = -40.3o = 40.3o S. of E.
Resulting momentum =
X/Cos A = 7.20^10^5/Cos(-40.3) =