Asked by Sotha Bun
2. Two pickup trucks crash at a 90 degree intersection. If the momentum of pickup A is
4.60 x10^4 kg km/h north and the momentum of pickup B is 6.25 x 10^4 kg km/h
east, what is the magnitude of the resulting momentum of the final mass?
4.60 x10^4 kg km/h north and the momentum of pickup B is 6.25 x 10^4 kg km/h
east, what is the magnitude of the resulting momentum of the final mass?
Answers
Answered by
Henry
Resulting momentum:
M1*V1 + M2*V2 = 4.60*10^4i + 6.25*10^4.
Tan A = Y/X =4.60*10^4/6.25*10^4 = 0.736, A = 36.4o
Res. Momentum = X/Cos36.4 = 6.25*10^4/Cos36.4 = 7.76*10^4 kg km/h.
M1*V1 + M2*V2 = 4.60*10^4i + 6.25*10^4.
Tan A = Y/X =4.60*10^4/6.25*10^4 = 0.736, A = 36.4o
Res. Momentum = X/Cos36.4 = 6.25*10^4/Cos36.4 = 7.76*10^4 kg km/h.
Answered by
Henry
Remember that the total momentum
before the collision = The total momentum after the collision.
before the collision = The total momentum after the collision.
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