Asked by Tyreice
A bank account was opened with a deposit of $2750 at an APR of 3.5% compounded one of the following ways. Find the amount in this account after 6 years with compounding of:
(round answers to nearest 100th)
annually: $
semi-annually: $
quarterly: $
monthly: $
weekly: $
daily: $
1000 times a year: $
10,000 times a year: $
(round answers to nearest 100th)
annually: $
semi-annually: $
quarterly: $
monthly: $
weekly: $
daily: $
1000 times a year: $
10,000 times a year: $
Answers
Answered by
Damon
r = .035/n where n = times per year
yearly gain = 1+r
final amount = 2750 * (1+r)^6n
so for example for 1000 times per year:
r = .035/1000 = .000035
1+r = 1.000035
and amount = 2750 *(1.000035)^6000
= $ 3392.60
yearly gain = 1+r
final amount = 2750 * (1+r)^6n
so for example for 1000 times per year:
r = .035/1000 = .000035
1+r = 1.000035
and amount = 2750 *(1.000035)^6000
= $ 3392.60
Answered by
Damon
gain per period = 1+r
not per year
gain per year = (1+r)^n
gain per 6 years = (1+r)^6n
not per year
gain per year = (1+r)^n
gain per 6 years = (1+r)^6n
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