Asked by elamin
Calculate the mass of benzoic acid required to prepare 100cm3 each of 0.1m,0.25m, and 0.5m solutions
Answers
Answered by
bobpursley
I assume your m should be Molarity, M.
mass=molartiy*molmass*volumeinLiters
mass=.1*molmassBenzoicAcid*.1m^3
so the mom mass is 122g/mole, so we have
mass=.1 Mole/liter*122g/mole*.1 Liter= 1.22 grams
check my thinking.
mass=molartiy*molmass*volumeinLiters
mass=.1*molmassBenzoicAcid*.1m^3
so the mom mass is 122g/mole, so we have
mass=.1 Mole/liter*122g/mole*.1 Liter= 1.22 grams
check my thinking.
Answered by
Benjamin's
M =molar.volume. molar mass÷1000
314×220×1.28÷ 1000
= 0.535
314×220×1.28÷ 1000
= 0.535
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