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A right angled triangle has sides a and b where a<b. If the right angle is bisected then then find the distance between orthoce...Asked by sivakumar
A right angled triangle has sides a and b where a<b. If the right angle is bisected then then find the distance between orthocentres of the smaller triangles using coordinate geometry.
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Answered by
Steve
http://formulas.tutorvista.com/math/orthocenter-formula.html
This will give you the orthocenter, if you have the vertices of a triangle.
If you set up your right triangle with the right angle at C=(0,0) then let the other two vertices be at A=(a,0) and B=(0,b).
Then the right-angle bisector intersects the hypotenuse at D=(d,d) where d = ab/(a+b). (why?)
Now you have the vertices for your two smaller triangles. Find their orthocenters and then the distance between them.
This will give you the orthocenter, if you have the vertices of a triangle.
If you set up your right triangle with the right angle at C=(0,0) then let the other two vertices be at A=(a,0) and B=(0,b).
Then the right-angle bisector intersects the hypotenuse at D=(d,d) where d = ab/(a+b). (why?)
Now you have the vertices for your two smaller triangles. Find their orthocenters and then the distance between them.
Answered by
Hitler
Haula samjha re? Question poochhe toh wapis poochhra.. kutta kaata terku?
Answered by
Anonymous
False
Answered by
Anonymous
Pls give clarity for the question