Asked by Tyler
How do I factor this question?
3n^2-n-4=
3n^2-n-4=
Answers
Answered by
Steve
You know the factors will be
(3n-?)(n+?)
or
(3n+?)(n-?)
where the ?? pairs are 1,4 or 2,2
So, just poke around a bit and you will soon find that
(3n-4)(n+1)
works
(3n-?)(n+?)
or
(3n+?)(n-?)
where the ?? pairs are 1,4 or 2,2
So, just poke around a bit and you will soon find that
(3n-4)(n+1)
works
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