A 14.7 mL sample of 0.0550 M KOH solution required 55.5 mL of aqueous acetic acid solution in a titration experiment. Calculate the molarity of the acetic acid solution.

1 answer

HAc = acetic acid

HAc + KOH ==> KAc + H2O

mols KOH = M x L = ?
Convert mols KOH to mols HAc. Since 1 mol HAc = 1 mol KOH (from the coefficients), then mols HAc = mols KOH.
Then M HAc = mols HAc/L HAc = ?