HAc = acetic acid
HAc + KOH ==> KAc + H2O
mols KOH = M x L = ?
Convert mols KOH to mols HAc. Since 1 mol HAc = 1 mol KOH (from the coefficients), then mols HAc = mols KOH.
Then M HAc = mols HAc/L HAc = ?
A 14.7 mL sample of 0.0550 M KOH solution required 55.5 mL of aqueous acetic acid solution in a titration experiment. Calculate the molarity of the acetic acid solution.
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