Question
a car is used to move a crest of mass of 645kg on a horizontal road the horizontal force exerted is 15000n the coefficient of kinetic friction is 0.8 calculate the acceleration of the car
Answers
Henry
M*g = 645 * 9.8 = 6321 N. = Wt. of of the mass. = Normal force, Fn.
Fex = 15,000 N.
Fk = u*Fn = 0.8 * 6321 = 5057 N. = Force of kinetic friction.
Fex-Fk = M*a. a = ?.
Fex = 15,000 N.
Fk = u*Fn = 0.8 * 6321 = 5057 N. = Force of kinetic friction.
Fex-Fk = M*a. a = ?.