Asked by Sara
A thin-walled sphere rolls along the floor. What is the ratio of its translational kinetic energy to its rotational kinetic energy through its center of mass?
Answers
Answered by
bobpursley
RE=1/2 *I w^2=.5*v^2/r^2
But I=2/5 mr^2
so TE/Re= (1/2 mv^2)/(Mr^2*v^2/5)=2.5
check
But I=2/5 mr^2
so TE/Re= (1/2 mv^2)/(Mr^2*v^2/5)=2.5
check
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.