Question
Write a balanced equation for the reaction that occurs in each of the following cases. (Use the lowest possible coefficients. Include states-of-matter under SATP conditions in your answer.)
I think have the reactions, but I'm stuck with the states of matter. Any help would be much appreciated :)
(a) Cesium is added to water.
2Cs (s) + 2H_2O (l) --> 2CsOH(s) + H_2(aq)
(b) Strontium is added to water.
Sr(s) + 2H_2O(l) --> Sr(OH)_2(s) + 2H_2(aq)
(c) Sodium reacts with oxygen.
4Na(s) + O_2(g) --> 2Na_2O (s)
(d) Calcium reacts with iodine.
Ca(s) + I_2(l) --> CaI_2(s)
I think have the reactions, but I'm stuck with the states of matter. Any help would be much appreciated :)
(a) Cesium is added to water.
2Cs (s) + 2H_2O (l) --> 2CsOH(s) + H_2(aq)
(b) Strontium is added to water.
Sr(s) + 2H_2O(l) --> Sr(OH)_2(s) + 2H_2(aq)
(c) Sodium reacts with oxygen.
4Na(s) + O_2(g) --> 2Na_2O (s)
(d) Calcium reacts with iodine.
Ca(s) + I_2(l) --> CaI_2(s)
Answers
in (a) and (b), the hydroxides are probably in solution and the hydrogen is evolved as a gas
Thanks scott! Just a quick correction, the reaction in part C is actually 2Na + O_2 --> Na_2O_2
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