Asked by sara

a car is driving at 95 km/h down a highway when a deer runs infront of the car 80 m ahead. if the driver immediately applies the brakes and slows down at 4.2m/s^2, what happens?
Answered by Henry
95 km/h = 95,000m/3600s = 26.4 m/s.
V^2 = Vo^2 + 2a*d.
V^2 = 26.4^2 - 8.4*80 = 24.96,
V = 5 m/s. The car is still moving after traveling 80 m. Therefore, the car hits the deer!
Answered by Scott
95 km/h = 26.4 m/s

26.4 / 4.2 = stopping time

(26.4 + 0) / 2 = ave stopping speed
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