A 10-kg disk-shaped flywheel of radius 9.0 cm rotates with a rotational speed of 320 rad/s.

Determine the rotational momentum of the flywheel.
With what magnitude rotational speed must a 10-kg solid sphere of 9.0 cm radius rotate to have the same rotational momentum as the flywheel?

User Icon for bobpursley bobpursley answered
7 years ago

Look up the moment of inertia for a disk, and the sphere.

flywheel(disk)=Ifly*w
sphere=Isphere*ws
set them equal, solve for ws
put radii in meters...

User Icon for Explain Bot Explain Bot answered
11 months ago

To determine the rotational momentum of the flywheel, we can use the formula for rotational momentum, which is given by:

Rotational momentum (L) = mass (m) * angular velocity (ω)

Given that the mass of the flywheel is 10 kg and the rotational speed is 320 rad/s, we can calculate the rotational momentum as follows:

L = m * ω
= 10 kg * 320 rad/s
= 3200 kg·m²/s

Therefore, the rotational momentum of the flywheel is 3200 kg·m²/s.

Now, let's find the magnitude of the rotational speed that a 10-kg solid sphere must have to have the same rotational momentum as the flywheel.

The moment of inertia (I) for a solid sphere is given by the formula:

I = (2/5) * m * r²

Where m is the mass of the sphere and r is its radius.

The rotational momentum of the sphere can be calculated using the formula mentioned earlier, L = I * ω.

Setting the rotational momenta of the flywheel and the sphere equal to each other, we can solve for the magnitude of the rotational speed (ω) of the sphere:

L_flywheel = L_sphere

m_flywheel * ω_flywheel = I_sphere * ω_sphere

10 kg * 320 rad/s = (2/5) * 10 kg * (0.09 m)² * ω_sphere

3200 kg·m²/s = (2/5) * (0.09 m)² * ω_sphere

Simplifying the equation, we can solve for ω_sphere:

ω_sphere = (5 * 3200 kg·m²/s) / ((2/5) * (0.09 m)²)

ω_sphere = 71111.1 rad/s

Therefore, the magnitude of the rotational speed that the 10-kg solid sphere must have to have the same rotational momentum as the flywheel is approximately 71111.1 rad/s.