Asked by Evelyn
I'm stuck on a couple of similar problems involving pH and acids/bases
1) What is the final pH of a 1L solution that is initially .15 M HF and .2 M NaF after 10 mL of .02 M HCl has been added? Ka=7.2x10^-4
Do i just calculate the total mols of H and divide by the volume, then find the pH?
2.) Calculate the volume of .030 M HNO3 that must be added to a 100mL solution of .25 M NaOh to give a pH of 8.5
This question deals with a strong acid/base, so would I do the same procedure as I would do for number 1? Or would I use a different approach?
Thanks!
1) What is the final pH of a 1L solution that is initially .15 M HF and .2 M NaF after 10 mL of .02 M HCl has been added? Ka=7.2x10^-4
Do i just calculate the total mols of H and divide by the volume, then find the pH?
2.) Calculate the volume of .030 M HNO3 that must be added to a 100mL solution of .25 M NaOh to give a pH of 8.5
This question deals with a strong acid/base, so would I do the same procedure as I would do for number 1? Or would I use a different approach?
Thanks!
Answers
Answered by
DrBob222
The first problem is a buffer problem. HF is a weak acid and NaF is the salt of the weak acid. Use the Henderson-Hasselbalch equation.
The second problem is a strong acid/strong base problem. There are no ionization constants involved and you can go from molarities to H^+ and pH.
Post your work if you get stuck.
The second problem is a strong acid/strong base problem. There are no ionization constants involved and you can go from molarities to H^+ and pH.
Post your work if you get stuck.
Answered by
Evelyn
Thanks! I figured out how to do the buffer problem. Can I use the Henderson-Hasselbalch equation for the strong acid/base problem with 0 for the pKa?
Answered by
DrBob222
No. The H-H equation has no meaning for a strong acid/strong base because neither HNO3 nor NaOH has a Ka or Kb.
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