Asked by clara
Suppose that a person closes a car door. The person's fingers are in the door opening, that is located 0.50 m from the hinges. The rotational inertia of the car door is 5.0 kg⋅m2. The door closes in 0.1 s and the rotational speed of the door is 1.4 rad/s just before it closes
Determine the average force that the car door exerts on the person's fingers
Determine the average force that the car door exerts on the person's fingers
Answers
Answered by
bobpursley
yep, it will hurt.
torque*time=I*w
force*distane*time=I*w
you have distance, time, I, and w
solve for force.
I get on the order of 140 N
torque*time=I*w
force*distane*time=I*w
you have distance, time, I, and w
solve for force.
I get on the order of 140 N
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