Asked by clara
A car leaves an intersection after a light turns green. It starts from rest and reaches a speed of 13.4 m/s in 5.0 s. The radius of a tire of the car is 0.25 m.
Answers
Answered by
bobpursley
and the question is?
Answered by
Damon
What is the question?
a = (13.4-0)/5 m/s^2 = r*alpha
v = 0 + a t = r*omega
d = 0 + 0t + (1/2)(5)t^2
a = (13.4-0)/5 m/s^2 = r*alpha
v = 0 + a t = r*omega
d = 0 + 0t + (1/2)(5)t^2
Answered by
clara
what is the rotational acceleration?
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