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A 3.60 102-kg piano is being lifted at a steady speed from ground level straight up to an apartment 18.0 m above the ground. Th...Asked by Delli
a 300kg piano is being lifted at a steady speed from ground level straight up to an apartment 10.0m above ground. The crane that is doing the lifting produces a steady power of 400 W. How much time does it take to lift the piano?
Answers
Answered by
drwls
Time required (s) = (Work required, J)/(Power, W)
The amount of work required is
W= M g *(10 meters) = 300*9.8*10 Joules
Finish the calculation
The amount of work required is
W= M g *(10 meters) = 300*9.8*10 Joules
Finish the calculation
Answered by
Natasha
Thanks
Answered by
kc
P = 400 W
m = 300 kg
g = 9.8m/s²
d = 10.0 m
t = ?
P = Fd/t = mgd/t
P = mgd/t
Pt/P = mgd/P *divide both sides by "P"*
t = mgd/P
t = (300 kg)(9.8m/s²)(10.0m)/400 W
t = 29400 kg-m²/s²/400 W
t = 73.5 s
m = 300 kg
g = 9.8m/s²
d = 10.0 m
t = ?
P = Fd/t = mgd/t
P = mgd/t
Pt/P = mgd/P *divide both sides by "P"*
t = mgd/P
t = (300 kg)(9.8m/s²)(10.0m)/400 W
t = 29400 kg-m²/s²/400 W
t = 73.5 s
Answered by
nethmi
thank you👍😊
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