Asked by Anon
When kevin commuted to work one morning, his average speed was 45 mph. He averaged only 30 mph for the return trip because of an accident on the highway. If the total time for the round trip was 50 min determine the distance between his place of work and his home.
Answers
Answered by
Henry
50 min. = 5/6 h.
t h. = time to get to work.
(5/6-t) h. = time to return home.
r1 * t = r2 * (5/6-t)
45 * t = 30 * (5/6-t).
45t = 25 - 30t, t = 1/3 h.
5/6-t = 5/6 - 1/3 = 5/6 - 2/6 = 3/6 = 1/2 h.
d v= 45 * 1/3 = 15 mi.
t h. = time to get to work.
(5/6-t) h. = time to return home.
r1 * t = r2 * (5/6-t)
45 * t = 30 * (5/6-t).
45t = 25 - 30t, t = 1/3 h.
5/6-t = 5/6 - 1/3 = 5/6 - 2/6 = 3/6 = 1/2 h.
d v= 45 * 1/3 = 15 mi.
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