Question

find a quadratic function in standard form for each set of points.
(-1,2),(0,1),(1,-4)

Answer 1

y=ax^2+bx+c

a) 2=a-b+c
b) 1= c
c) -4=a+b+c

from equation b< c=1
add a)+c)
-2=2a+2*1
a=-2

then in equation c)
-4=-2+b+1
b= -3

y=ax^2+bx + c
y=-2x^2-3x+1

Answer 2

thank you very much