Question

a piece of copper weighing 400g is heated to 100degree celsius and then quickly transfered to a copper calorimeter of mass 10g containing 100g of liquid of unknown specific heat capacity at 30 degree celsius.if the final temperature of the mixture is 50 degree celsius,calculate the specific heat capacity of the liquid

Answer 1

sum of heats added is zero.
Heat added to liquid+heataddedtocopper=0
100*C*(50-30)+400*Ccu*(50-100)=0
look up specific heat Ccu of copper, and solve for C

Answer 2

41.96g

Answer 3

Hello, please attach the answers to your questions...
Thanks!

Answer 4

Please send formula

Answer 5

Thanks♡︎

Answer 6

The formula is H=ML
L=H/M
WHERE M (ICE) =M3-M2
H= MC (@1-@2)
M= WATER ( M1-M2)

Answer 7

Given;
M1= 400g
M2= 10g
M3= 100g
@1= 100
@2= 30
@3= 50
C=
H= M*L
L= H/M
M3-M2
@1-@2
M2-M1

Answer 8

Write out the parameters
And check c(SHC) with c =C/M