Asked by joke
                a piece of copper weighing 400g is heated to 100degree celsius and then quickly transfered to a copper calorimeter of mass 10g containing 100g of liquid of unknown specific heat capacity at 30 degree celsius.if the final temperature of the mixture is 50 degree celsius,calculate the specific heat capacity of the liquid
            
            
        Answers
                    Answered by
            bobpursley
            
    sum of heats added is zero.
Heat added to liquid+heataddedtocopper=0
100*C*(50-30)+400*Ccu*(50-100)=0
look up specific heat Ccu of copper, and solve for C
    
Heat added to liquid+heataddedtocopper=0
100*C*(50-30)+400*Ccu*(50-100)=0
look up specific heat Ccu of copper, and solve for C
                    Answered by
            surbhi
            
    41.96g
    
                    Answered by
            George 
            
    Hello, please attach the answers to your questions...
Thanks!
    
Thanks!
                    Answered by
            Borrislyn
            
    Please send formula
    
                    Answered by
            Nur-ana
            
    Thanks♡︎
    
                    Answered by
            Victor
            
    The formula is H=ML 
L=H/M
WHERE M (ICE) =M3-M2
H= MC (@1-@2)
M= WATER ( M1-M2)
    
L=H/M
WHERE M (ICE) =M3-M2
H= MC (@1-@2)
M= WATER ( M1-M2)
                    Answered by
            Victor
            
    Given;
M1= 400g
M2= 10g
M3= 100g
@1= 100
@2= 30
@3= 50
C=
H= M*L
L= H/M
M3-M2
@1-@2
M2-M1
    
M1= 400g
M2= 10g
M3= 100g
@1= 100
@2= 30
@3= 50
C=
H= M*L
L= H/M
M3-M2
@1-@2
M2-M1
                    Answered by
            Newboy
            
    Write out the parameters
And check c(SHC) with c =C/M
    
And check c(SHC) with c =C/M
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