Asked by joke
a piece of copper weighing 400g is heated to 100degree celsius and then quickly transfered to a copper calorimeter of mass 10g containing 100g of liquid of unknown specific heat capacity at 30 degree celsius.if the final temperature of the mixture is 50 degree celsius,calculate the specific heat capacity of the liquid
Answers
Answered by
bobpursley
sum of heats added is zero.
Heat added to liquid+heataddedtocopper=0
100*C*(50-30)+400*Ccu*(50-100)=0
look up specific heat Ccu of copper, and solve for C
Heat added to liquid+heataddedtocopper=0
100*C*(50-30)+400*Ccu*(50-100)=0
look up specific heat Ccu of copper, and solve for C
Answered by
surbhi
41.96g
Answered by
George
Hello, please attach the answers to your questions...
Thanks!
Thanks!
Answered by
Borrislyn
Please send formula
Answered by
Nur-ana
Thanks♡︎
Answered by
Victor
The formula is H=ML
L=H/M
WHERE M (ICE) =M3-M2
H= MC (@1-@2)
M= WATER ( M1-M2)
L=H/M
WHERE M (ICE) =M3-M2
H= MC (@1-@2)
M= WATER ( M1-M2)
Answered by
Victor
Given;
M1= 400g
M2= 10g
M3= 100g
@1= 100
@2= 30
@3= 50
C=
H= M*L
L= H/M
M3-M2
@1-@2
M2-M1
M1= 400g
M2= 10g
M3= 100g
@1= 100
@2= 30
@3= 50
C=
H= M*L
L= H/M
M3-M2
@1-@2
M2-M1
Answered by
Newboy
Write out the parameters
And check c(SHC) with c =C/M
And check c(SHC) with c =C/M