Asked by joke

a piece of copper weighing 400g is heated to 100degree celsius and then quickly transfered to a copper calorimeter of mass 10g containing 100g of liquid of unknown specific heat capacity at 30 degree celsius.if the final temperature of the mixture is 50 degree celsius,calculate the specific heat capacity of the liquid

Answers

Answered by bobpursley
sum of heats added is zero.
Heat added to liquid+heataddedtocopper=0
100*C*(50-30)+400*Ccu*(50-100)=0
look up specific heat Ccu of copper, and solve for C
Answered by surbhi
41.96g
Answered by George
Hello, please attach the answers to your questions...
Thanks!
Answered by Borrislyn
Please send formula
Answered by Nur-ana
Thanks♡︎
Answered by Victor
The formula is H=ML
L=H/M
WHERE M (ICE) =M3-M2
H= MC (@1-@2)
M= WATER ( M1-M2)
Answered by Victor
Given;
M1= 400g
M2= 10g
M3= 100g
@1= 100
@2= 30
@3= 50
C=
H= M*L
L= H/M
M3-M2
@1-@2
M2-M1
Answered by Newboy
Write out the parameters
And check c(SHC) with c =C/M

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