Asked by jayden

One leg of a right angle triangle is always 6 meters long, and the other
leg is increasing at a rate of 2 meters per second. Find the rate of change of the hypotenuse when it is 10 meters long.

plz help

Answers

Answered by Steve
h^2 = 6^2 + x^2
h dh/dt = x dx/dt

when h=10, x=8, so just plug in the numbers

10 dh/dt = 8*2
dh/dt = 8/5 m/s
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