Asked by Mable
it is assumed that f is differentiable and that w has an absolute maximum at t0
w(t)= f(t)/(c+t)
derivative is f'(t)(c+t)-f(t)/(c+t)^2
Show that f(t0) = f′(t0)(C + t0).
I'm having a bit of trouble in the above question. I keep getting f(t0)= (c+t0)-f'(t0) instead of f(t0) = f′(t0)(C + t0).
Help is always appreciated :)
w(t)= f(t)/(c+t)
derivative is f'(t)(c+t)-f(t)/(c+t)^2
Show that f(t0) = f′(t0)(C + t0).
I'm having a bit of trouble in the above question. I keep getting f(t0)= (c+t0)-f'(t0) instead of f(t0) = f′(t0)(C + t0).
Help is always appreciated :)
Answers
Answered by
Steve
if w has a max at t0, dw/dt = 0 at t0.
so,
(f'(t0)(c+t0)-f(t0))/(c+t0)^2 = 0
so,
(f'(t0)(c+t0)-f(t0))/(c+t0)^2 = 0
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