Asked by Gbotty
A commitee consists of six men and four women.A randomly chosen subcommittee is made up of three of the committee members.What is the probability that (a) they are all women (b) two of them are men
Answers
Answered by
Reiny
prob(all women)
= C(4,3)/C(10,3) = ...
prob(two men, 1 woman)
= C(6,2)*C(4,1)/C(10,3) = ....
= C(4,3)/C(10,3) = ...
prob(two men, 1 woman)
= C(6,2)*C(4,1)/C(10,3) = ....
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