Asked by Martin
A driver jumps off the 3.0m diving board with an initial velocity of 5.0m/s. (a) Determine the maximum height, (b) The time to reach the maximum height, (c) The time it took to touch the water, and (c) The speed when touching the water.
Answers
Answered by
bobpursley
assuming the initial velocity is nearly straight upwards...
at max height, velocity is zero
0=5-9.8t
time to max height= 5/9.8 seconds
time to water:
hf=hi+vi*t-4.8t^2
0=3+5*t-4.9t^2
solve this quadratic equation for t.
speed:
vf=5*t-9.8t^2 put in t, and you have it.
at max height, velocity is zero
0=5-9.8t
time to max height= 5/9.8 seconds
time to water:
hf=hi+vi*t-4.8t^2
0=3+5*t-4.9t^2
solve this quadratic equation for t.
speed:
vf=5*t-9.8t^2 put in t, and you have it.
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