Asked by Scott
Silicon Carbide, SiC, is prepared by heating silicon dioxide in the presence of graphite. Carbon dioxide is the by-product of the reaction. How many grams of silicon carbide can be formed from the reaction of 50.0 grams fo graphite with 50.0 grams of silicon dioxide?
Answers
Answered by
DrBob222
This looks like a limiting reagent (LR) problem.
SiO2 + 2C ==> SiC + CO2
mols SiO2 = grams/molar mass = approx 50/60.1 = approx 0.0832
mols C = 50/12 = approx 0.0416
mols SiC formed using just SiO2 = 1:1; therefore, 0.0832.
mols SiC formed using just C = 0.0416 x 1/2 = 0.0208 so C is the limiting reagent and the amount of SiC formed is the SMALLER of the two possible answers.
grams SiC = mols SiC x molar mass SiC = ?
SiO2 + 2C ==> SiC + CO2
mols SiO2 = grams/molar mass = approx 50/60.1 = approx 0.0832
mols C = 50/12 = approx 0.0416
mols SiC formed using just SiO2 = 1:1; therefore, 0.0832.
mols SiC formed using just C = 0.0416 x 1/2 = 0.0208 so C is the limiting reagent and the amount of SiC formed is the SMALLER of the two possible answers.
grams SiC = mols SiC x molar mass SiC = ?
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