Asked by Anonymous
differentiate the cube root of (1+3xsquare)square.everytin over x
Answers
Answered by
Steve
f(x) = (1+3x^2)^(1/3) / x
f'(x) =
((1/3)(1+3x^2)^(-2/3) * 6x)(x) - (1+3x^2)^(1/3)(1)
----------------------------------------------------
x^2
-(x^2+1)
-------------------------
x^2 (1+3x^2)^(2/3)
f'(x) =
((1/3)(1+3x^2)^(-2/3) * 6x)(x) - (1+3x^2)^(1/3)(1)
----------------------------------------------------
x^2
-(x^2+1)
-------------------------
x^2 (1+3x^2)^(2/3)
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