Question
A particle travelling in a straight line with constant acceleration and starting from rest covers 36m in the 5th second.Find the acceleration and the distance traveled in the 6th second
Answers
after 4 s, the velocity is 4*a
after 5 s, the velocity is 5*a
the average velocity in the 5th sec is
... (5a + 4a) / 2 = 4.5a
4.5a = 36 ... a = 8 m/s^2
after 5 s, the velocity is 5*a
the average velocity in the 5th sec is
... (5a + 4a) / 2 = 4.5a
4.5a = 36 ... a = 8 m/s^2