Asked by Brooke
                A coil of wire has a resistance of 31.8Ω at 28 °C and 55.6Ω at 53 °C. What is the temperature coefficient of resistivity?
            
            
        Answers
                    Answered by
            Henry
            
    R = Ro + a(T2-T1)*Ro.
55.6 = 31.8 + a(53-28)31.8.
55.6 = 31.8 + 795a, a = 0.03/deg. C = Temp. coefficient.
    
55.6 = 31.8 + a(53-28)31.8.
55.6 = 31.8 + 795a, a = 0.03/deg. C = Temp. coefficient.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.