Asked by Brooke
A coil of wire has a resistance of 31.8Ω at 28 °C and 55.6Ω at 53 °C. What is the temperature coefficient of resistivity?
Answers
Answered by
Henry
R = Ro + a(T2-T1)*Ro.
55.6 = 31.8 + a(53-28)31.8.
55.6 = 31.8 + 795a, a = 0.03/deg. C = Temp. coefficient.
55.6 = 31.8 + a(53-28)31.8.
55.6 = 31.8 + 795a, a = 0.03/deg. C = Temp. coefficient.
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