a (x-2)(x-3) = 0
a[ x^2 -5x + 6 ] = 0
f(x) = a[ x^2 -5x + 6 ]
when x = 1
f(1) = 12 = a[ 1-5+6]
12 = 2 a
a = 6
so
f(x) = 6x^2 -30 x + 36
Form a quadratic statement from the given:
Zeroes at 2 and 3, f(1)=12.
f(x)=?
1 answer
1 answer