Asked by Nicole
The horizontal surface on which the block slides is frictionless. The speed of the block before it touch the spring is 6.0 m/s. How fast is the block moving at the instant the spring has been compressed 0.15 m? The spring constant, k = 2000 N/m
Answers
Answered by
bobpursley
initial KE=finalKE+springPEgained
1/2 m6^2=1/2 m vf^2+1/2 (2000)(.15^2)
without knowing mass m, you can't do much here.
vf^2=36-2000(.15^2)/m
1/2 m6^2=1/2 m vf^2+1/2 (2000)(.15^2)
without knowing mass m, you can't do much here.
vf^2=36-2000(.15^2)/m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.