Asked by Abaskisszy
The sum of the interior angels of a regular polygon 1800.calculate the size of one exterior angel of the polygon
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Answered by
Anonymous
sum of angles of any polygon is 180*(n-2) where n is the number of sides in the polygon.
1800/180 = 10, 10+2= 12. there are 12 sides
1800/12 =150 degrees
1800/180 = 10, 10+2= 12. there are 12 sides
1800/12 =150 degrees
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