Asked by Anonymous
sulfuric acid can be prepared by a multistep process summarized as: 2 SO2 + O2 + 2 H2O--> 2 H2SO4 What mass of sulfuric acid could be produced daily by a process using 38 kg per day of sulfuric dioxide with a 70% conversion efficiency ("yield"), assuming that sulfuric dioxide is the limiting reagent
Answer: 41 kg/day
I don't know how to get this answer. someone help!
Answer: 41 kg/day
I don't know how to get this answer. someone help!
Answers
Answered by
DrBob222
mols SO2 = 38000/molar mass SO2 = ?
mols H2SO4 produced = same as mols SO2 becaue 2 mol SO2 = 2 mol H2SO4.
Then grams H2SO4 = mols H2SO4 x molar mass H2SO4 = ? g, then convert to kg. That's if the process were 100% efficiency. It isn't so that answer x 0.70 = the amount produced at 70% efficiency.
mols H2SO4 produced = same as mols SO2 becaue 2 mol SO2 = 2 mol H2SO4.
Then grams H2SO4 = mols H2SO4 x molar mass H2SO4 = ? g, then convert to kg. That's if the process were 100% efficiency. It isn't so that answer x 0.70 = the amount produced at 70% efficiency.
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