Asked by nicole
how many grams of mercury II Nitrate will you need to prepare 500mL of a .60 M solution ?
Answers
Answered by
bobpursley
mass=volumeinLites*molmass*conc
=.5*molmassHg(NO3)2*.6
and you have to figure the mol mass of Hg(NO3)2
=.5*molmassHg(NO3)2*.6
and you have to figure the mol mass of Hg(NO3)2
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