Asked by CL
How much energy (in kj) is required to ionize 2.78 moles of hydrogen atoms
the right answer is: 3.65x10^3 kj
wondering how they got this answer.
the right answer is: 3.65x10^3 kj
wondering how they got this answer.
Answers
Answered by
DrBob222
E = 2.18E-18 J x (1/1 - 1/0) = 2.180E-18 J x (1 kJ/1000J) x 2.78 mol H atoms x 6.02E23 atoms/mol = ?
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