∆PRT is isosceles
∠PRT is 180-30 = 150
So, ∠P and ∠T are (180-150)/2 = 15°
PT^2 = 1^2 + 1^2 - 2(1)(1)cos150°
= 2+√3
Consider ∆PQT and you can get tan T
In triangle PQR, angle Q= 90 degrees, angle P= 60 degrees and angle R= 30 degrees. PR= 1 unit. Extend side QR to T such that PR= RT. Join PT.
Calculate the exact measure of angle T.
Determine the exact value of lengths needed to find tan T and then find tan T.
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