Question
a particle starts at time t=0 and moves on a number line so that its position at time t is given by x(t)= (t-2)^3(t-6)
what is the farthest to the left of the origin that the particles moves??
i was able to find the velocity and acceleration formula. but i have no idea how to do this
what is the farthest to the left of the origin that the particles moves??
i was able to find the velocity and acceleration formula. but i have no idea how to do this
Answers
Related Questions
a particle starts at time t = 0 and moves along the x axis so that its position at any time t>= 0 is...
F=6kt
This force acts on a particle of mass "m" that moves along a line. If the particle starts fro...
A particle moves along a vertical line. Its position in m at time t in s is given by s(t) = t3 – 9t2...
A particle moves along a straight line with the equation of motion s(t) = 1/3t^3 - 2t^2 + 3t where t...