Question

So I have the following differential equation.

The general solution I have is:

t=k(-1/r)+c

I now need to find the particular solution when t=0 and the radius (r) = 1cm.

So k is a constant which is approx 3.9 (5/4pi)

So for the particular solution im really just plugging in the numbers to find the value of c, is that correct?

Thanks

Answers

Anon
Just to add, by doing what I described above my answer for c would be the same value as for k (i.e 3.9 or 5/4pi) so my particular solution would be.

t=k(-1/r)+5/4pi

Steve
yes, c=k, so if k = 5π/4,

t = k (1 - 1/r)
= 5π/4 (1 - 1/r)
Anon
Thanks Steve.

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