Question

use the remainder theorem to find the remainder when P(x) = x^4-9x^3-5x^2-3x+4 is divided by x + 3

please help me start this problem I have no idea

Answer 1

did you actually read the Remainder Theorem?

It says that the remainder when P(x) is divided by (x-a) is P(a). So, you want to just plug in -3 for x.

P(-3) = (-3)^4-9(-3)^3-5(-3)^2-3(-3)+4
= 81+243-45+9+4
...

Answer 2

Thank you