Asked by Diana
A cubic block initially at rest slides with a constant acceleration on an inclined plane 10m long in 2s. Calculate the acceleration of the block.
Answers
Answered by
Steve
s = 1/2 at^2
so,
1/2 * a * 2^2 = 10
a = 5 m/s^2
assuming, of course, that the block slid the entire length of the plane ...
so,
1/2 * a * 2^2 = 10
a = 5 m/s^2
assuming, of course, that the block slid the entire length of the plane ...
Answered by
Hala
givens=vi=0m/s,displacement=10m,t=2s>>
>>average acceleration=average velocity/time interval
>>average velocity=diplacement/time interval
>>average velocity=10m/2s=5m/s
>>average acceleration=5/2=2.5m/s^2
i hope this helps :)
>>average acceleration=average velocity/time interval
>>average velocity=diplacement/time interval
>>average velocity=10m/2s=5m/s
>>average acceleration=5/2=2.5m/s^2
i hope this helps :)
Answered by
Anonymous
Hala - acceleration = total change in velocity/time, not average
a = 10 /2 = 5 m/s^2
what is in your mind I think is total distance = average speed *time
a = 10 /2 = 5 m/s^2
what is in your mind I think is total distance = average speed *time
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