Asked by yara
A ‘moving sidewalk’ in an airport terminal moves at 1 m/s and is 35 m long. If a woman steps on at one end and walks 1.5 m/s relative to the sidewalk, in the same direction as the movement of sidewalk. (a) How much time does it take her to reach the opposite end? 14s (b) What if she steps on the opposite side, walking against the motion of the sidewalk, what must be her speed so that she reaches the end of the track in the same time as in part (a)?
Xo=0...
Xo=0...
Answers
Answered by
Anonymous
moving at 2.5 m/s relative to ground
t = 35 m/2.5 m/s
moving at (v-1) m/s
same t
35 = (v-1) t
solve for v
t = 35 m/2.5 m/s
moving at (v-1) m/s
same t
35 = (v-1) t
solve for v
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