Asked by Daniela
From the top of the control tower 250 m tall, an airplane is sighted on the ground below. If the airplane is 170 m from the base of the tower, find the angle of depression of the airplane from the top of the control tower.
Answers
Answered by
Scott
tan(Θ) = 250/170
Answered by
Anonymous
10.0
Answered by
Erika
From the top of the control tower 250 m tall, an airplane is sighted on the ground below. If the airplane is 170 m from the base of the tower, find the angle of depression of the airplane from the top of the control tower
Answered by
dhine
YEs
Answered by
Anonymous
|\
| \
| \
| \
| \
| \
| \
| ( ß ) \
base ———————— boat
of the x
airplane
Tan= Opposite/Adjacent
Tan ß = 250m/170m
Tan ß = 1.470588235
Since we are looking for angle theta's value, we need to press:
Shift+Tan+1.470588235 = 55.78429786 m is the angle of depression of the airplane from the top of the control tower.
(We should always answer in a complete sentence of atleast label you answer. Peace.)
| \
| \
| \
| \
| \
| \
| ( ß ) \
base ———————— boat
of the x
airplane
Tan= Opposite/Adjacent
Tan ß = 250m/170m
Tan ß = 1.470588235
Since we are looking for angle theta's value, we need to press:
Shift+Tan+1.470588235 = 55.78429786 m is the angle of depression of the airplane from the top of the control tower.
(We should always answer in a complete sentence of atleast label you answer. Peace.)
Answered by
Rafaela
Tan= Opposite/Adjacent
Tan ß = 250m/170m
Tan ß = 1.470588235
Since we are looking for angle theta's value, we need to press:
Shift+Tan+1.470588235 = 55.78429786 m is the angle of depression of the airplane from the top of the control tower.
(Sorry, I can't show you how the right triangle or the figure will look like. But we should always answer in a complete sentence of atleast label you answer. Peace.)
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