Asked by Rocky

system of linear equations of substitution.
a=2/b-3

a=2b-8
Answered by Steve
a = 2b-8, so (assuming the usual sloppiness with parentheses)

2b-8 = 2/(b-3)
(b-4)(b-3) = 1

Now just solve the quadratic. I suspect a typo, just fyi.
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