Vo = 17m/s[39o].
Xo = 17*Cos39 = 13.2 m/s.
Yo = 17*sin39 = 10.70 m/s.
A. d = Xo*t. 3.8 = 13.2*t, t = 0.288 s.
B. h = Yo*t +0.5g*t^2.
h = 10.7*0.288 - 4.9*0.288^2 = 2.67 m.
In a friendly game of handball, you hit the ball essentially at ground level and send it toward the wall with a speed of 17 m/s at an angle of 39 ∘ above the horizontal.
How long does it take for the ball to reach the wall if it is 3.8 m away?
How high is the ball when it hits the wall?
1 answer