Asked by Keisha morris
How many minutes would be required for a 310.0 W immersion heater to heat 202.0 g of water from 22.0°C to 95.6°C?
Answers
Answered by
Scott
Joules of energy required
... 202 * (95.6 - 22.0) * 4.18
divide by heater wattage
... 1 watt = 1 Joule per second
divide by 60 ... sec to min
... 202 * (95.6 - 22.0) * 4.18
divide by heater wattage
... 1 watt = 1 Joule per second
divide by 60 ... sec to min
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.