Asked by Kate_Mack_Son
I have this extra credit assignment for Algebra 1. It's due tomorrow and I really need help on this.
I had a slope of 0.222 for one line and 0.081 for the other line. (y=0.081 * x + 215.378) (y=0.222 * x - 43.829) My intersection point is about 1800,320.
I have to solve for both equations using substitution to make sure the intersection is correct. Please help.
I had a slope of 0.222 for one line and 0.081 for the other line. (y=0.081 * x + 215.378) (y=0.222 * x - 43.829) My intersection point is about 1800,320.
I have to solve for both equations using substitution to make sure the intersection is correct. Please help.
Answers
Answered by
Steve
Looks like you're a bit off. See
http://www.wolframalpha.com/input/?i=solve+y%3D0.081+*+x+%2B+215.378,+y%3D0.222+*+x+-+43.829
Doing the substitution, I get
y=0.081 * x + 215.378
so,
0.081x + 215.378 = 0.222x - 43.829
0.141x = 259.207
x = 1838.3475
y = 364.2841
Not sure how you could come close, but yet be wrong.
wolframalpha.com is a good place to check your work
http://www.wolframalpha.com/input/?i=solve+y%3D0.081+*+x+%2B+215.378,+y%3D0.222+*+x+-+43.829
Doing the substitution, I get
y=0.081 * x + 215.378
so,
0.081x + 215.378 = 0.222x - 43.829
0.141x = 259.207
x = 1838.3475
y = 364.2841
Not sure how you could come close, but yet be wrong.
wolframalpha.com is a good place to check your work
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