Asked by Rachel
f=p(c-1)-c(p-1)
sOLVE FOR p
f=pc-p-cp+c
pc - cp = 0
So now we have f = -p+c
Move "p" by itself.
f-c = -p
Now we multiply each side by -1
p = c-f
Let's plug in values for f and c to check. We'll say:
f=2
c=3
p=3-2
p=1 in this case. Now, let's plug in the same values in the original equation.
2=p(3-1)-3(p-1)
2=3p-p-3p+3
2-3=-p
-1=-p
OR
1=p
So the answer: p=c-f
Took me forever to figure that out since I forgot to chance a negative to a positive when I multiplied. Glad I made it through though :)
Matt
sOLVE FOR p
f=pc-p-cp+c
pc - cp = 0
So now we have f = -p+c
Move "p" by itself.
f-c = -p
Now we multiply each side by -1
p = c-f
Let's plug in values for f and c to check. We'll say:
f=2
c=3
p=3-2
p=1 in this case. Now, let's plug in the same values in the original equation.
2=p(3-1)-3(p-1)
2=3p-p-3p+3
2-3=-p
-1=-p
OR
1=p
So the answer: p=c-f
Took me forever to figure that out since I forgot to chance a negative to a positive when I multiplied. Glad I made it through though :)
Matt
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