Asked by Nicole
When heated, KClO3 decomposes into KCl and O2. If this reaction produced 79.9 g of KCl, how much O2 was produced (in grams)?
Answers
Answered by
Scott
2 KClO3 ---> 2 KCl + 3 O2
moles O2 = 3/2 * moles KCl
moles KCl = mass KCl / molar mass KCl
mass O2 = moles O2 * molar mass O2
moles O2 = 3/2 * moles KCl
moles KCl = mass KCl / molar mass KCl
mass O2 = moles O2 * molar mass O2
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