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explain how to do these with please. I was out a couple of days so give clear instructions. sin(π/2-ϴ)secϴ cot(π/2-x)cosϴAsked by save me
explain how to do these with please. I was out a couple of days so give clear instructions.
1. sin(π/2-ϴ)secϴ
2. cot(π/2-ϴ)cosϴ
1. sin(π/2-ϴ)secϴ
2. cot(π/2-ϴ)cosϴ
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Answered by
bobpursley
You have a few identities for complementary angles
a. sin(PI/2-Theta)=cosTheta
b. ctn(PI/2-Theta)=tanTheta
1. that becomes sec*cos=1
2. that becomes Tan*cos=sinTheta
http://www2.clarku.edu/~djoyce/trig/identities.html
a. sin(PI/2-Theta)=cosTheta
b. ctn(PI/2-Theta)=tanTheta
1. that becomes sec*cos=1
2. that becomes Tan*cos=sinTheta
http://www2.clarku.edu/~djoyce/trig/identities.html
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