Asked by Anonymous
                can someone help me with this problem y=x^2 -9 represents the velocity of an object over the interval [1, 5] in meters per second.  What is the displacement of the object over the time interval?
            
            
        Answers
                    Answered by
            Damon
            
    I am a physicist so call your y "v", velocity and your x is "t"
d = integral v dt
d is integral from 1 to 5 of
(t^2 -9) dt
= t^3/3 - 9t
at 5 - at 1
at 5 it is 125/3 - 45
at 1 it is 1/3 - 9
-------------------subtract
124/3 - 36
    
d = integral v dt
d is integral from 1 to 5 of
(t^2 -9) dt
= t^3/3 - 9t
at 5 - at 1
at 5 it is 125/3 - 45
at 1 it is 1/3 - 9
-------------------subtract
124/3 - 36
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