Question
a 5.4 kg ball slides along a friction-less, horizontal surface at 6.2 m/s. The ball then encounters a ramp which slopes upward. The ball slides up the ramp, slowing down until it stops and slides back down. what is the kinetic energy of the ball as it slides along the friction- less, horizontal surface? What is the maximum height reached by the ball as it slides up the slope?
Answers
Damon
ke = (1/2)(5.4) (6.2)^2
stops so all ke converted to U
U = m g h = ke from first part
5.4 (9.81) h = answer from part 1
stops so all ke converted to U
U = m g h = ke from first part
5.4 (9.81) h = answer from part 1